x^2-1.5*x+.50=0

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Solution for x^2-1.5*x+.50=0 equation:


Simplifying
x2 + -1.5x + 0.50 = 0

Reorder the terms:
0.50 + -1.5x + x2 = 0

Solving
0.50 + -1.5x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-0.50' to each side of the equation.
0.50 + -1.5x + -0.50 + x2 = 0 + -0.50

Reorder the terms:
0.50 + -0.50 + -1.5x + x2 = 0 + -0.50

Combine like terms: 0.50 + -0.50 = 0.00
0.00 + -1.5x + x2 = 0 + -0.50
-1.5x + x2 = 0 + -0.50

Combine like terms: 0 + -0.50 = -0.5
-1.5x + x2 = -0.5

The x term is -1.5x.  Take half its coefficient (-0.75).
Square it (0.5625) and add it to both sides.

Add '0.5625' to each side of the equation.
-1.5x + 0.5625 + x2 = -0.5 + 0.5625

Reorder the terms:
0.5625 + -1.5x + x2 = -0.5 + 0.5625

Combine like terms: -0.5 + 0.5625 = 0.0625
0.5625 + -1.5x + x2 = 0.0625

Factor a perfect square on the left side:
(x + -0.75)(x + -0.75) = 0.0625

Calculate the square root of the right side: 0.25

Break this problem into two subproblems by setting 
(x + -0.75) equal to 0.25 and -0.25.

Subproblem 1

x + -0.75 = 0.25 Simplifying x + -0.75 = 0.25 Reorder the terms: -0.75 + x = 0.25 Solving -0.75 + x = 0.25 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '0.75' to each side of the equation. -0.75 + 0.75 + x = 0.25 + 0.75 Combine like terms: -0.75 + 0.75 = 0.00 0.00 + x = 0.25 + 0.75 x = 0.25 + 0.75 Combine like terms: 0.25 + 0.75 = 1 x = 1 Simplifying x = 1

Subproblem 2

x + -0.75 = -0.25 Simplifying x + -0.75 = -0.25 Reorder the terms: -0.75 + x = -0.25 Solving -0.75 + x = -0.25 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '0.75' to each side of the equation. -0.75 + 0.75 + x = -0.25 + 0.75 Combine like terms: -0.75 + 0.75 = 0.00 0.00 + x = -0.25 + 0.75 x = -0.25 + 0.75 Combine like terms: -0.25 + 0.75 = 0.5 x = 0.5 Simplifying x = 0.5

Solution

The solution to the problem is based on the solutions from the subproblems. x = {1, 0.5}

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